Question

u will get 28 marks nd i will mark u brainliest .....plzzzz....Solve this problem with full method...

Answer 1

Hey Mate !

Here is your solution :

Let the unit digit is ' y '.

And , tens digit is ' x '.

=> Sum of digits = 10

=> x + y = 10 ----------- ( 1 )

So,

Number = 10x + y.

It is given that if 18 is subtracted from number then the digits in new number is equal.i.e. ten's place digit is equal to one's place digit.

Let , the digit in new number be z.


New number = 10z + z = 11z.

A/Q,

=> 10x + y - 18 = 11z

=> 9x + x + y - 18 = 11z

Substituting the value of ( 1 ),

=> 9x + 10 - 18 = 11z

=> 9x - 8 = 11z

=> ( 9x - 8 ) / 11 = z

Here,

We have to find such a value of 'x' ( 1 to 9 )that when it is multiplied by 9 and subtracted by 8 then divided by 11 should be positive and 1 digit number.

Now,

x can't be 1,2,3,4,5,6,8,9 as if x will be one of these numbers then z will be a fraction that's not possible.

Hence, x = 7

By substituting the value of x in ( 1 ),

=> x + y = 10

=> 7 + y = 10

=> y = 10 - 7

•°• y = 3

Number = 10x + y

= 10 × 7 + 3

= 70 + 3

= 73.

Hence, the required number is 73.

Special thanks to Siddhartha Bhaiya !



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Hope it helps !! ^_^

Answer 2

Let the digit at ten's place be x and the digit at one's place be y.

Therefore the original number = 10x + y  ----- (1)

Given that sum of digits of a two digit number is 10.

= > x + y = 10.

= > y = 10 - x  ------ (2)


Given that if 18 is subtracted from its digits in the resulting number will be =.

= > 10x + y - 18 = 10x - 20 + y + 2

= > 10x + y = 10(x - 2) + (y + 2).

= > x - 2 = y + 2

= > x - 2 = 10 - x + 2

= > x - 2 = 12 - x

= > 2x = 14

= > x = 7.


Substitute x = 7 in (2), we get

= > y = 10 - 7

= > y = 3.


Substitute x and y in (1), we get

= >10x + y

= > 10(7) + 3

= > 70 + 3

= > 73.



Therefore the number is 73.


Hope this helps!