Question

Uaing the laws of set algebra prove that (aub)n(aub')=a

Answer 1

• Answer:

$\bf{(A\cup{B})\cap(A\cup{B'})=A}$

Step-by-step explanation:

$\text{Concept used:}\\\\\text{Distributive law:}$

$A\cup{(B\cap{C})}=(A\cup{B})\cap(A\cup{C})$

$\text{Given:}$

$(A\cup{B})\cap(A\cup{B'})$

$=A\cup{(B\cap{B'})}\:\:\text{(using distributive law)}$

$=A\cup{(\emptyset)}$

$=A\cup{\emptyset}$

$=A$

$\implies(A\cup{B})\cap{(A\cup{B'})}=A$

Answer 2

Answer:

Step-by-step explanation:

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