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1)The solution of equation 4m
=O is m=
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If equation ax
2
+bx+c=0, then the roots are equal (coincident) when b
2
−4ac=0.
In equation x
2
−(2+m)+1(m
2
−4m+4)=0
The a=1 b=−(2+m) c=m
2
−4m+4
Thenb
2
−4ac={(−(2+m))}
2
−4(1)(m
2
−4m+4)=0
⇒m
2
+4m+4−4m
2
+16m−16=0
⇒−3m
2
+20m−12=0⇒−3m
2
+18m+2m+6=0
−3m(m−6)+2(m−6)=0⇒(−3m+2)(m−6)=0
If -3m+2=0 then m=
3
2
If m−6=0 then m=6
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