Ues. a car is 250 metres behind the bus. the car and bus are moving with speed 60 km/hr and 35 km/hr respectively. the car will be ahead of bus by 250 metres in:
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1
in this process the car have to cover 250+250=500metres relative to bus.
relative velocity of car wrt bus=60-35=25m/s.
so time taken to complete 500m relative distance with 25m/s relative velocity
=500/25=20sec
relative velocity of car wrt bus=60-35=25m/s.
so time taken to complete 500m relative distance with 25m/s relative velocity
=500/25=20sec
Answered by
20
Hello there,
● Answer-
t = 72 s
● Explanation-
Let vb and vc be speed of car and bus respectively.
Relative speed of car is given by-
vcb = vc - vb
vcb = 60 - 35
vcb = 25 km/h
vcb = 6.95 m/s
Total distance car have to overtake -
s = 250 + 250
s = 500 m
Time taken is calculated by
t = s / vcb
t = 500 / 6.95
t = 72 s
Therefore, the car will be ahead of bus in 72 s.
Hope it helps...
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