Question

uestion 3
In the figure given below, O is the centre of the circle and AB is a diameter.
If AC = BD and angleAOC = 72º. Find:
(1) angleABC
(ii) andleBAD
(iii) angleABD
​

Answer 1

Answer:

solution..

angleAOC=ARC AC....... INSCRIBED ANGLE THRM

72°=AC

1)

angle abc= 1/2arc ac.... inscribed angle them

=1/2×72°

=36°

angle abc=36°

2)

arc ac=arc bd......arcs corresponding to congruent chords

>>bd=72°

angle bad =1/2arc bd .... inscribed angle thrm

=1/2×72°

=36°

angle bad