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If one root of the equation ix2 – 2(1 + i)X + (2-1) = 0 is 2-i, then the other root is
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Step-by-step explanation:
One root of the equation ix
2
−2(i+1)x+(2−i)=0 is 2−i
Let the other root is α
α(2−i)= 2-i/i
⇒α=1/i =−i ..... [∵i^2 =−1]
Therefore, −i is the other root.
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