Ujjwal takes 3 hours more than Amit to walk 30 km but if ujwal Doubles his speed he is ahead of Amit by 3/2 hours. find the speed of walking
Answers
Answer:
Amit's speed is 5 km/h and Ujjwai's speed is 10/3 km/h
Step-by-step explanation:
Define x:
Let Amit takes x hours to walk 30 km
Ujjwai takes (x + 3) hours to walk 30 km
Find the speed of of Amit:
Speed = Distance ÷ Time
Speed = 30/x
Find the speed of Ujjwat:
Speed = Distance ÷ Time
Speed = 30/(x + 3)
If Ujjwai doubles his speed:
Speed = 30/(x + 3) x 2
Speed = 60/(x + 3)
Find the time Ujjwai took
Time = Distance ÷ Speed
TIme = 30 ÷ 60/(x + 3) = (x + 3)/2
Solve x:
Ujjwai is 3/2 hour faster
x - (x + 3)/2 = 3/2
2x - (x + 3) = 3
2x - x - 3 = 3
x = 6 hours
Find the time each of them took:
Amit = x = 6 hours
Ujjwai = x + 3 = 6 + 3 = 9 hours
Find their speed:
Speed = Distance ÷ Time
Amit's speed = 30 ÷ 6 = 5 km/h
Ujjwai's speed = 30/9 = 10/3 km/h
Answer: Amit's speed is 5 km/h and Ujjwai's speed is 10/3 km/h
Answer:
Speed of Ujjwal = 6.67 kph
Step-by-step explanation:
Let say
Hours taken by Amit to walk 30 km = x
Hours taken by Ujjwal to walk 30 km = x + 3
As we know
Distance covered by Ajjwal = Distance covered by Amit ...(1)
As
So equation (1) would become
v₁ (x + 3) = v₂ (x) ....(2)
Now After Ujwal doubles his speed
Time taken by Ujwal =
So, again as we know distance covered as same so our new equation is
2v₁ () = v₂ (x)
v₁ (2x - 3) = v₂ (x) .... (3)
Comparing equation 2 and 3
v₁ (2x - 3) = v₁ (x + 3)
cancelling same terms on both sides
2x - 3 = x + 3
2x - x = 3 + 3
x = 6 hours
So, it means initially
Time take by Amit to travell 30km = 6 hours
Speed of Amit = 30 ÷ 6 = 5 kph (Kilometer per hour)
Time take by Ujjwal to travell 30km = 6 + 3 = 9 hours
Speed of Ujjwl = 30 ÷ 9 = 3.34 kph (Kilometer per hour)
However, later on
Speed of Ujjwal = 2 x Initial Speed of Ujjwal
Speed of Ujjwal = 2 x 3.34 = 6.67 kph
Time take by Ujjwal to travell 30km = 6 - (3÷2) = 4.5 hours