Question

ulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.10.10, point, 1. The probability of her getting injured playing soccer is \dfrac{1}{10}
10
1
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start fraction, 1, divided by, 10, end fraction.

Answer 1

Complete question: Paulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.1. The probability of her getting injured playing soccer is 1/10. Which of these events is more likely?

Solution:

'More likely' means to have the probability of occurrence of one event more than the other events.

While polling volleyball, probability of getting hurt is

P(A) = 0.1

and in the case of soccer, it is

P(B) = 1/10

i.e., P(B) = 0.1

Here we see, P(A) = P(B)

Answer: We can conclude that no event is more likely to occur than the other, i.e., the probability of occurrence for each event is equally likely.