Question

ULIU. Uimension of the other side. 3. A wall of a room is of dimensions 5m X 4m. It has a window of dimensions 1.5m X 1m and a door of dimensions 2.25m X 1m. Find the area of the wall that is to be painted.​

Answer 1

Answer:

Given,a wall of a room is of dimensions 5 m x m.

∴ Length of the room = 5 m and breadth of the room = 4 m

∴ Area of the room = l x b=5 x 4 = 20 m2

Also, length of the window = 1.5 m and breadth of the window = 1 m

∴ Area of the window = l x b = 1.5 x 1 = 1.5 m2

Now, length of the door = 2.25 m and breadth of the door = 1 m

∴ Area of the door = l x b = 2.25 x 1 = 2.25 m2

Now, area of the wall to be painted

= Area of the room – (Area of the window + Area of the door) = 20 – (1.5 + 2.25) = 20 – 3.75

= 16.25 m2

Answer 2

Step-by-step explanation:

Given,a wall of a room is of dimensions 5 m x m. ∴ =>Length of the room = 5 m and breadth of the room = 4m

=>Area of the room = l x b=5 x 4 = 20 m^2 Also, length of the window = 1.5 m and breadth of the window = 1m

=>Area of the window = l x b = 1.5 x 1 = 1.5 m^2 Now, length of the door = 2.25 m and breadth of the door = 1 m

=> Area of the door = l x b = 2.25 x 1 = 2.25 m^2

Now, area of the wall to be painted

=> Area of the room – (Area of the window + Area of the door)

=>20 – (1.5 + 2.25)

=>20 – 3.75

=>16.25m^2