Question

Ultraviolet light of 6.2 eV falls on Caesium sur-face (work function = 1.2 eV). The kinetic en-ergy (in electron volts) of the fastest electronemitted is approximately ​

Answer 1

Answer:

very good question but i am not too bigger to solve urs question so sorry

Answer 2

Step-by-step explanation:

E=W+K.E

K.E=E−W

=6.2ev−4.2ev

=2ev

=3.2×10^-19J