Math, asked by nravilochanan, 1 day ago

ULU TUTU 7 12 4 1. Each side of a regular polygon is 2.5 cm in length. The perimeter of the polygon is 12.5cm. How many sides does the polygon have? 2. Michael finished colouring a picture in hour. Vaibhav finished colouring the same picture in hour. Who worked longer? By what fraction was it longer? 3. Find i) 2.5 x 0.3 ii) 156.1 x 100 ii) 7.75 = 0.25 4. The scores in mathematics test (out of 25) of 15 students is as follows: 19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20 Find the mode and media of this data. Are they same?​

Answers

Answered by rimaprajapati2611
0

Answer:

  1. The perimeter of a regular polygon is the sum of the lengths of all its equal sides = 12.5 cm. Length of each side = 2.5 cm. Thus, the number of sides = `12.5/2.5 = 125/25 = 5`. The polygon has 5 .

2.Solution:-

From the given details we get to know that

Time taken by the Michael to colour the picture is = (7/12)

Time taken by the Vaibhav to colour the picture is = (3/4)

We will convert the above fractions into like fractions by taking LCM

The LCM of 12, 4 = 12

Convertingthe given fraction into an equivalent fraction having 12 as the denominator.

(7/12) = (7/12) × (1/1) = 7/12

(3/4) = (3/4) × (3/3) = 9/12

Clearly, (7/12) < (9/12)

Hence, (7/12) < (3/4)

Therefore, Vaibhav worked for longer time.

Thus, Vaibhav worked longer time by = (3/4) – (7/12)

= (9/12) – (7/12)

= (9 – 7)/12

= (2/12)

= (1/6) of an hour.  

Answer

Vainhav worked longer for (1/6) of an hour.

3.Let's know the meaning of the terms "Mode" and "Median"

Mode = The no. which is occurring most frequently in a set of numbers is called Mode

Median = Median refers to the value which lie in the middle of the set of numbers (When arranged in ascending or descending order).

Now Coming to the question :-

First we will find the mode of the data :- 19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20

20 have occurred 4 times ∴

The most frequently occurring value =  20                                                                     Therefore the mode of the given set of data is 20

Now Median;

Numbers arranged in ascending order  = 5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25

So the middle value here is 20.

Median and Mode both are same.

Step-by-step explanation:

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