Math, asked by snehalkhaparde123, 11 months ago

Ulve any four of the following subquestions :
175
) Find the value of the determinantsolve quadratic equation 5 x square + 13 x + 8 is equal to zero ​

Answers

Answered by Anonymous
119

AnswEr :

\underline{\bigstar\:\textsf{Roots of the Given Quadratic Equation :}}

:\implies\tt 5x^2 + 13x + 8 = 0\\\\\qquad\scriptsize{\bf{\dag}\:\textsf{where, a = 5 ; b = 13 ; c = 8}}\\\\:\implies\tt x=\dfrac {-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\:\implies\tt x=\dfrac {-13\pm\sqrt{(13)^2-(4 \times 5 \times 8)}}{2 \times 5}\\\\\\:\implies\tt x=\dfrac {-13\pm\sqrt{169-160}}{10}\\\\\\:\implies\tt x= \dfrac{ - 13 \pm \sqrt{9} }{10}\\\\\\:\implies\tt x= \dfrac{ - 13 \pm3}{10}\\\\\\:\implies\tt x= \frac{ - 13 + 3}{10} \quad or \quad x = \dfrac{ - 13 - 3}{10}\\\\\\:\implies\tt x= \frac{ -10}{10} \quad or \quad x = \dfrac{ -16}{10}\\\\\\:\implies \boxed{ \red{\tt x=  - 1\quad or \quad x = \dfrac{ - 8}{5}}}

Answered by rajsingh24
35

IN GIVEN ATTACHMENT, WE ARE SOLVE THIS QUESTION ON TWO METHODS.

1. SOLVE BY QUADRATIC EQUATION.

2.SOLVE BY FACTORISATION METHOD.

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