Umar was watching the show standing on the
ground. A jet fighter when 1000m high passes
vertically above another jet fighter at an instant,
when the angle of elevation of the two jets from
Umer are 60% and 45° respectively. At what distance
(vertical) the pilots were flying the jets at that
instant? (2m)
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Step-by-step explanation:
height = AC = 300 m
angle of elevation = tan0= height / base = √3
3000/DC = √3
3000/ √3 = DC
1000√3 = DC
In ΔBCD
tan 45 = 1 = BC/ DC
BC/ 1000√3 = 1
BC = 1000√3
AB = 3000 - 1000√3
AB = 1268m this is the distance between two planes
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