Social Sciences, asked by Anonymous, 1 month ago

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The velocity of a body changes from 65 m/s - 98 m/s by Time of 12 s . What is distance covered by body if acceleration is 2.75 m/s2.​​

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Answered by studylover001
47

Answer:

Answer :

Using s = ut + 1/2 x at²

s = (65)(12) + 1/2 x (2.75) ( 12)²

s = 780 + 1/2 x 2.75 x 144

s = 780 + 1/2 x 396

s = 780 + 198

s = 978

Distance covered by body if acceleration is 2.75 m/s² is 978 m.

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