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Find p(O), p(1) and p(2) for each of the following polynomials:
(iv) p(x) = (x - 1)(x+1)
Answers
Step-by-step explanation:
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1
Secondary School Math 25 points
2. Find p(0), p(1) and p(2) for each of the following polynomials:
(i) p(y) = y2 – y + 1
(ii) p(t)=2+t+2+ -
(iii) p(x)= x
(iv) p(x)=(x-1)(x+1)
please give answer to all questions. I will give my full points.
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(i) 1, 1 and 3 respectively.
(ii) 4, 5 and 6 respectively.
(iii)0, 1 and 2 respectively.
(iv) -1, 0 and 3 respectively.
Step-by-step explanation:
We need to find p(0), p(1) and p(2) for each of the following polynomials.
(i)
The given polynomial is
P(y)=y^2-y+1
Substitute y=0,
P(0)=0^2-0+1=1
Substitute y=1,
P(1)=1^2-1+1=1
Substitute y=2,
P(2)=2^2-2+1=3
Therefore, p(0), p(1) and p(2) are 1, 1 and 3 respectively.
Similarly
(ii)
The given polynomial is
P(t)=2+t+2
Find p(0), p(1) and p(2).
P(0)=2+0+2=4
P(1)=2+1+2=5
P(2)=2+2+2=6
Therefore, p(0), p(1) and p(2) are 4, 5 and 6 respectively.
(iii)
The given polynomial is
p(x)=x
Find p(0), p(1) and p(2).
P(0)=0
P(1)=1
P(2)=2
Therefore, p(0), p(1) and p(2) are 0, 1 and 2 respectively.
(iv)
The given polynomial is
P(x)=(x-1)(x+1)
Find p(0), p(1) and p(2).
P(0)=(0-1)(0+1)=-1
P(1)=(1-1)(1+1)=0
P(2)=(2-1)(2+1)=3
Therefore, p(0), p(1) and p(2) are -1, 0 and 3 respectively.
Answer:
p(0) =(0-1)(0+1)
=-1+1=0 answer
p(1)=(1-1)(1+1)
=0*2=0 answer
p(2)=(2-1)(2+1)
=1*3=3answer
mark as a brainlist answer plzz