Question

un 1) What is the value of K if the roots are real and equal for 2x - 6x - k = 0 a) 0 b) 9/2 C) 3 d) -3​

Answer 1

Answer:

Given a quadratic equation, for which the coefficient of x2is given, the coefficient of x is given, but the constant term in the quadratic equation is not given. The constant is assigned a variable named k.

We have to find the variable k.

Given that the quadratic equation has real and equal roots.

If the discriminant of the quadratic expression is equal to zero, then the quadratic expression has equal real and equal roots.

The discriminant of the given quadratic expression 2x2−6x+k=0 is given by:

⇒(−6)2−4(2)(k)=0

⇒36−8k=0

From the above expression determining the value of k, as given below:

⇒k=368

∴k=92

Hence the value of k is 92.

The value of k is 92.

Answer 2

Answer:

• $2 x { - 6x + k - - 0}^{2}$