Math, asked by shiladalvi25, 23 hours ago

un 1) What is the value of K if the roots are real and equal for 2x - 6x - k = 0 a) 0 b) 9/2 C) 3 d) -3​

Answers

Answered by AlliumCepa
0

Answer:

b) 9/2

Step-by-step explanation:

The discriminant of an equation when the roots are equal is 0.

(b^{2} - 4ac = 0)

Eq:- 2x^{2}-6x^{}-k = 0     [a=2, b = -6, c = k]

Here, discriminant = (-6)(-6) - 4*2*k = 0

36 - 8k = 0

36 = 8k

36/8 = k

9/2 = k

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