Question

Un figure C and D are on the semi-circle described on BA as diameter. Given
BAD = 70° and ZDBC = 30°. Calculate ZABD and ZBDC.
300
70ºA​

Answer 1

Step-by-step explanation:

<BDA=90 [angle at the circumference of a semi circle]

then

<ABD+<70+<90=180

or, <ABD=20

Again

<70+<BCD=180

or <BCD=110

30+20+70+90+110+<BDC=360

orBCD=40