Un Lyuui uislalile ITUNI e PUML ALU, JOITU DI-4,5).
Q31. A box contains 90 discs which are numbered from 1 to 90 if one disc is drawn at random from the box, find the
probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 7.
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Step-by-step explanation:
Solution(i):
Let E be the event of drawing a disc from the box of discs numbered from 1 to 90
Two digit numbers from 1 to 90=10,11,12,.....,90
No. of favorable outcomes=81
Total no. of possible outcomes =90
We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=9081=109
Therefore, the probability of a two digit numbered disc from the box of discs numbered from 1 to 90=109
Solution(ii):
Let F be the event of drawing a perfect square numbered disc from the box of discs numbered from 1 to 90
Perfect square numbers from 1 to 90=1,4,9,16,25,36,49,64,81
No. of favorable outcomes=9
Total no. of possible outcomes =90
We know that, Probability P(F) =(Total no.of possible outcomes)(No.of favorable outcomes)=909=101
Therefore, the probability of drawing a perfect square numbered disc from the box of discs numbered from 1 to 90=101
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