Question

Un Places. In the following figure, PQ || SR, SA || BQ and PDS = 48°. Find (RCB, X, Y, (Refer Exercise-4.4, T.B Pg. No:82) AP 480 R B Contd....3​

Answer 1

Answer:

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Step-by-step explanation:

Given, PQ⊥PS,PQ∥SR,∠SQR=28∘,∠QRT=65∘

According to the question,

x+∠SQR=∠QRT (Alternate angles  as QR is transversal.)

⇒x+28∘=65∘

⇒x=37∘

Also ∠QSR=x

⇒∠QSR=37∘

Also ∠QRS+∠QRT=180∘ (Linear pair)

⇒∠QRS+65∘=180∘

⇒∠QRS=115∘

Now, ∠P+∠Q+∠R+∠S=360∘ (Sum of the angles in a quadrilateral.)

⇒90∘+65∘+115∘+∠S=360∘ 

⇒270∘+y+∠QSR=360∘

⇒270∘+y+37∘=360∘ 

⇒307∘+y=

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Answer 2

Answer:

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