Question

UN
WS
Two
unbiased
dice are thrown . find the
probability total
number on the dice
the dice is greater than
10​

Answer 1

Answer:

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Answer 2

Answer:

GIVEN: Two dice are thrown  

Here, two dice are thrown, so possible outcomes are :  

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),

Hence, total number of outcomes = 36

Let E = Event of  getting the total of numbers on the dice is greater than 10

Here,the total of numbers on the dice greater than 10 are (5, 6), (6, 5) and (6, 6)

Number of outcomes favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E4) = 3/36 = 1/12

Hence, the probability of getting the total of numbers on the dice greater than 10 = 1/12 .

Explanation: