Question

Unbalanced forces of magnitude 50 N and 30 N are applied on the block of mass M (20 kg) as shown in the figure. If the horizontal surface is smooth then which of the following statements is correct?



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Answer 1

Answer:

Hᴇʟʟᴏᴡ ᴄᴜᴛᴛɪᴇ ᴘɪᴇ ʜᴜᴍ ʜᴀɪɴ ɴᴀ .

Yᴏᴜʀ ᴀɴsᴡᴇʀ✰:-

Horizontal force,F=600 N

Horizontal force,F=600 NMass of body A, m

Horizontal force,F=600 NMass of body A, m 1

Horizontal force,F=600 NMass of body A, m 1

Horizontal force,F=600 NMass of body A, m 1 =10 kg

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kg

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kg

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a=

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= m

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF =

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600 =20m/s

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600 =20m/s 2

Horizontal force,F=600 NMass of body A, m 1 =10 kgMass of body B, m2=20 kgTotal mass of the system, m=m1+m2=30 kgUsing Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:F=ma a= mF = 30600 =20m/s 2

Answer 2

Unbalanced forces of magnitude 50 N and 30 N are applied on the block of mass M (20 kg) as shown in the figure. If the horizontal surface is smooth then which of the following statements is cor

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