Question

uncertainty in position of a particles of 25 gram in space is 10 to the power minus 5 metres. hence uncertainly in velocity (m/s) is​

Answer 1

Answer:

4.22 × 10^(−34)

Explanation:

dv × dx = h/(4πm)

dv × 5 = 6.626 × 10^(−34)/4 × 3.14 × .025

dv = 4.22 × 10^(−34)