Question

Uncertainty in position of an electron is 1nm. Calculate its uncertainty in velocity.

(Given, h = 6.626 x 10−34. )​

Answer 1

Answer:

We have the relation,

(∆ x) /(∆ v) = h/4πm......... 1

Here, h= 6.626x 10^-34 JS= 6.626x 10^-27 erg sec, ∆ x= 1 nm= 1x 10^-7 cm

We know,

m= 9.1x 10^-28 g

∆ v= 6.626x 10^-27 erg sec/4x 3.142x 9.1x 10^-28 gx 1x 10^-7 CM

= 6.62x 10^-27 /114.37x 10^-35 CM/sec

= 0.579x 10^ 7 CM/ sec....

Thank you

Answer 2

Explanation:

we have the relation *(∆X) / (∆V) =h/4πm...................1