Question

uncertainty in position of an electron moving with a velocity of 3×10^4cm/s accurate up to 0.00l% will be ?​

Answer 1

Answer:

According to Heisenbergs uncertainty principle

Δx.Δp ≥ h/4π

The uncertainty in position Δx is

Δx ≥ h/4πΔp

h = 6.626 x 10 ^-34 Js

Δp = mΔv

Given

Δv/v = 0.001% = 10^-5

Δv = v x 10^-5 = 3 x 10^-3 m/s

m = 9.1 x 10^-31kg

Δp = 9.1 x 10^-31kg x 3 x 10^-3 m/s

= 27.3 x 10^-34 kgm/s

4πΔp = 3.43 x 10^-32 kgm/s

Δx ≥ h/4πΔp

Δx ≥ 6.626 x 10^-34 / 3.43 x 10^-32 kgm/s

Δx ≥ 1.93 x 10^-2 m

Δx ≥ 19.3 mm

Hence the uncertainty in position is greater than 19.3 millimeters

Answer 2

Answer:

Answer:

According to Heisenbergs uncertainty principle

Δx.Δp ≥ h/4π

The uncertainty in position Δx is

Δx ≥ h/4πΔp

h = 6.626 x 10 ^-34 Js

Δp = mΔv

Given

Δv/v = 0.001% = 10^-5

Δv = v x 10^-5 = 3 x 10^-3 m/s

m = 9.1 x 10^-31kg

Δp = 9.1 x 10^-31kg x 3 x 10^-3 m/s

= 27.3 x 10^-34 kgm/s

4πΔp = 3.43 x 10^-32 kgm/s

Δx ≥ h/4πΔp

Δx ≥ 6.626 x 10^-34 / 3.43 x 10^-32 kgm/s

Δx ≥ 1.93 x 10^-2 m

Δx ≥ 19.3 mm

Hence the uncertainty in position is greater than 19.3 millimeters

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Explanation: