Question

Uncle Jason is twice as old as his nephew Ralph, and 10 years ago he was three times as old as Ralph. Find their present ages.

Answer 1

Answer:

here your answer................

Step-by-step explanation:

let the present ages of Jason and his

nephew Ralph is 2x and x

10 year's ago their ages,

Jason=2x-10,

and

Ralph=x-10.

According to question

2x-10=3(x-10)

2x-10=3x-30

2x-3x=-30+10

-x=-20

x=20

therefore the present ages of Jason

is 2x=2×20=40 year's.

and

his nephew Ralph age 20 year's.

Answer 2

Let present age of Jason be "M" years and present age of Ralph be "N" years.

Uncle Jason is twice as old as his nephew Ralph.

According to question,

→ M = 2 × N

→ M = 2N _____ (eq 1)

Ten years ago, he was three times as old aa Ralph.

Now,

• Age of Jason = (M - 10) years
• Age of Ralph = (N - 10) years

According to question,

→ M - 10 = 3(N - 10)

→ M - 10 = 3N - 30

→ M - 3N = - 30 + 10

→ 2N - 3N = - 20 [From (eq 1)]

→ - N = - 20

→ N = 20

Put value of N in (eq 1)

→ M = 2(20)

→ M = 40

∴ Present age of uncle Jason is 40 years and present age of his nephew Ralph is 20 years.

______________________________

✯ Verification :

From above calculations we have M = 40 and N = 20

According to question, we have equations :

1) M = 2N

2) M - 10 = 3(N - 10)

Put value of M and N in (eq 1)

=> 40 = 2(20)

=> 40 = 40

Similarly, put value of M and N in (eq 2)

=> 40 - 10 = 3(20 - 10)

=> 30 = 3(10)

=> 30 = 30