Question

UNCUT - Numerical
Ma
0 30
Heat capacity (C) of an ideal gas is X KJ/mole/K. To rise its temperature from 298K to 318K ,
heat to be supplied per 10g gas will be in KJ) [MW = 16]
AO
16X
ВО
6.25%
СО
32X
DO
12.5%
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Answer 1

Explanation:

q=nCv∆T

=10/16×X×(318-298)

=5/8×X×20

=25/2×X

=12.5X kj