under 760 mm Hg.
3 g
100 g of liquid A (molar mass 140 g moll) was dissolved in 1000 g of liquid B
(molar mass 180 g mol-'). The vapour pressure of pure liquid B was found to be
500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure
in the solution if the total vapour pressure of the solution is 475 Torr.
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Answer:
Given: PT=475,WA=100g,MA=140,PBo=500
WB=1000g,MB=180,PAo?,PA=?
PT=PAoXA+PBoXB⟶(1) & XA+XB=1⟶(2)
⇒XAXB=WAMBWBMA=100×1801000×140=7.78
∴XB=7.78XA
Substituting XB
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