Question

under 760 mm Hg.
3 g
100 g of liquid A (molar mass 140 g moll) was dissolved in 1000 g of liquid B
(molar mass 180 g mol-'). The vapour pressure of pure liquid B was found to be
500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure
in the solution if the total vapour pressure of the solution is 475 Torr.​

Answer 1

Answer:

Given: PT=475,WA=100g,MA=140,PBo=500

WB=1000g,MB=180,PAo?,PA=?

PT=PAoXA+PBoXB⟶(1) & XA+XB=1⟶(2)

⇒XAXB=WAMBWBMA=100×1801000×140=7.78

∴XB=7.78XA

Substituting XB