Question

Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V. If the length of capillary is doubled and the diameter of the bore is halved, the rate of flow would become?

Answer 1

Hello guys

So from Poiseuille's formula

Rate of flow (v) is proportional to R*4

V1=r*4/l

V2 =r*4/32l

So by taking ratio we get answer

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