Science, asked by priyaranjansahoo083, 7 months ago

under a force 10i -3j+ 8k newton a body of mass 5kg moves form position 6i+ 5j- 3k to 10i- 2j + 7k the work done by the force is =?

Answers

Answered by suhail2070

Answer:

141 JOULES

Explanation:

$work \: done = f.s \\ =(10i - 3j + 8k).((10 - 6)i + ( - 2 - 5)j + (7 - ( - 3))k) \\ = (10i - 3j + 8k).(4i - 7j + 10k) \\ = 40 + 21 + 80 \\ = 141 \: joules$

Previous Question

Next Question

Similar questions

English, 3 months ago

Arun saw a bird which _on a branch of a tree. (a)is sitting (b)was sitting (c)has sat (d)had sat...

Physics, 3 months ago

which one of the following is the fuction of bones humen body...

Science, 3 months ago

define area of cross section...

Computer Science, 7 months ago

information on cheque is sorted using...

Hindi, 7 months ago

what is the sangam period in South indian history...

English, 1 year ago

passengers are...... to smoke in the train. ( allow )...

Science, 1 year ago

What is analogous organ ...

Science, 1 year ago

example of free energy sources...

under a force 10i -3j+ 8k newton a body of mass 5kg moves form position 6i+ 5j- 3k to 10i- 2j + 7k the work done by the force is =?​

Answers

under a force 10i -3j+ 8k newton a body of mass 5kg moves form position 6i+ 5j- 3k to 10i- 2j + 7k the work done by the force is =?