Question

under certain conditions, the equilibrium constant for the decomposition of pcl5 into pcl3 and cl2 is 00211 m/l. what are the concentrations of PC5,pcl3 and cl2 if initial concentration of pcl5 was 1 mole.​

Answer 1

Answer:

Total pressure is 3 atm.

Total number of moles =2+2+2=6

Number of moles of PCl

5

=2

Mole fraction of PCl

5

=

6

2

=0.333

Partial pressure of PCl

5

=0.333×3 atm=1 atm.

Number of moles of PCl

3

=2

Mole fraction of PCl

3

=

6

2

=0.333

Partial pressure of PCl

3

=0.333×3 atm=1 atm.

Number of moles of Cl

2

=2

Mole fraction of Cl

2

=

6

2

=0.333

Partial pressure of Cl

2

=0.333×3 atm=1 atm.

The equilibrium constant K

p

=

P

PCl5

P

PCl3

×P

Cl2

K

p

=

1

1×1

=1