Question

Under different conditions an element crystallizes in bcc and fcc having edges 300 and 400 pm respectively. The ratio of their densities would be​

Answer 1

Answer:

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Explanation:

Theoretical density of crystal, ρ=

N

o

a

3

nM

g/cm

3

For fcc, n=4; a=3.5×10

−8

cm

So, ρ

1

=

N

o

×(3.5)

3

×(10

−

8)

3

4×M

g/cm

3

.....(i)

For bcc, n=2; a=3×10

−8

cm

So, ρ

2

=

N

o

×(3)

3

×(10

−

8)

3

2×M

g/cm

3

.....(ii)

So (i)/(ii)

⇒

ρ(bcc)

ρ(fcc)

=

2×(3.5)

3

4×(3)

3

=

42.875

2×27

=

1

1.259

Hence, 1.259:1 is correct answer.

Answer 2

Answer:

1.259:1 is the correct answer please make me as brainlist

Explanation:

ANSWER

Theoretical density of crystal, ρ=

N

o

a

3

nM

g/cm

3

For fcc, n=4; a=3.5×10

−8

cm

So, ρ

1

=

N

o

×(3.5)

3

×(10

−

8)

3

4×M

g/cm

3

.....(i)

For bcc, n=2; a=3×10

−8

cm

So, ρ

2

=

N

o

×(3)

3

×(10

−

8)

3

2×M

g/cm

3

.....(ii)

So (i)/(ii)

⇒

ρ(bcc)

ρ(fcc)

=

2×(3.5)

3

4×(3)

3

=

42.875

2×27

=

1

1.259