Under identical conditions of pressure and temperature, 2 l of gaseous mixture of and effuses through a hole in 5 minutes whereas 2 l of a gas x of molecular mass 36 takes 10 minutes to effuse through the same hole. The mole ratio of in the mixture is:
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Answer:
Correct option is
D
1:1
Rate of diffusion is directly proportional to
(
MOLECULAR WEIGHT)
1
TIME∝
MOLECULAR WEIGHT
Now time is taken for mixture=5 min
time is taken for unknown gas =10 min
therefore
m
1
/5
=
10
36
m
1
=3
m
1
=9
MOLECULAR WEIGHT m
1
=
n
1
+n
2
n
1
M
1
+n
2
M
2
where n
1
and n
2
are number of moles of H
2
and CH
4
respectively
9=
(n
1
+n
2
)
n
1
×2+n
2
×16
9n
1
+9n
2
=2n
1
+16n
2
7n
1
=7n
2
n
1
=n
2
Therefore moles ratio is 1:1
Hence, the correct option is D
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