Chemistry, asked by Aadityarajak6082, 10 hours ago

Under identical conditions of pressure and temperature, 2 l of gaseous mixture of and effuses through a hole in 5 minutes whereas 2 l of a gas x of molecular mass 36 takes 10 minutes to effuse through the same hole. The mole ratio of in the mixture is:

Answers

Answered by prosy8964
0

Answer:

Correct option is

D

1:1

Rate of diffusion is directly proportional to

(

MOLECULAR WEIGHT)

1

TIME∝

MOLECULAR WEIGHT

Now time is taken for mixture=5 min

time is taken for unknown gas =10 min

therefore

m

1

/5

=

10

36

m

1

=3

m

1

=9

MOLECULAR WEIGHT m

1

=

n

1

+n

2

n

1

M

1

+n

2

M

2

where n

1

and n

2

are number of moles of H

2

and CH

4

respectively

9=

(n

1

+n

2

)

n

1

×2+n

2

×16

9n

1

+9n

2

=2n

1

+16n

2

7n

1

=7n

2

n

1

=n

2

Therefore moles ratio is 1:1

Hence, the correct option is D

Similar questions