Question

Under identical conditions of temperature and pressure the ratio of Rates of diffusion of O2 and CO2 gases is given by

Answer 1

The ratio of the rate of diffusion of helium and methane under identical conditions of pressure and temperature is

(a)4(b)2(c)1(d)0.5

A)  

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YHeYCH4=MCH4MHe−−−−√

=164−−−√

=2

Hence answer is (b)

Answer 2

Answer: 0.21

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{Rate_{O_2}}{Rate_{CO_2}}=\sqrt{\frac{M_{CO_2}}{M_{O_2}}}$

$\frac{Rate_{O_2}}{Rate_{CO_2}}=\sqrt{\frac{44}{32}$

Squaring both sides and solving:

$\frac{Rate_{O_2}}{Rate_{CO_2}}=0.21$

Hence, the ratio of rates of diffusion of $O_2$ and $CO_2$ gases is 0.21.