Question

Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is :
[Given that 1 L bar = 100 J ]
(1) - 30 J
(2) 5 kJ
(3) 25 J
(4) 30 J

Answer 1

Answer:

- 30J

Explanation:

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Answer 2

The work done by the gas is  -30 J

Step by step explanation:

Under isothermal condition the work done by the gas is calculated by the following formula.

                     $\bold{W_{irr}=-P_{ext}\Delta V}$.....................(1)

From the given,

Eternal pressure = 2 bar

Initial volume = 0.1 L

Final volume = 0.25L

Substitute the all given values in equation (1)

                    $W_{irr}=-2\times (0.25-0.1)L$

                            $\Rightarrow 0.30L-bar$

                           $\Rightarrow 0.30\times 100$

                           $\Rightarrow -300$

                          $\Rightarrow -30J$

Therefore, The work done by the gas is  -30 J

Hence, correct option is 1.