under ncc training program students of vidyalaya stayed in a conical tent made with a base radius of 7m and height 24m. after performing whole day program of ncc students came to their tent for some rest and enjoyment.
a. what is the slant height of the tent?
b.what is the area of the tarpaulin used in making the tent assuming that all the stiching margins and the wastage is negligible?
c. what is the length of the tarpaulin its width is 11m ?
d. determine the cost of tarpaulin if it measuring 1m²costs Rs.5
Answers
Right circular cone:
If a right angled triangle is revolved about
one of the two sides forming a right angle keeping the other side fixed in
position then the solid so obtained by segments is called right circular cone.
Slant height:
The length of the line segment joining the
vertex to any point on a circular edge of the base is called the slant height
of the cone.
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Given:
Radius of the base (r) = 24 m
Height of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know that
l²= r²+h²
l = √h²+r²
l = √10²+
24²
l = √100 + 576
l = 26 m
Slant height (l)= 26 m
(ii) Canvas required to make the conical tent =
Curved surface of the cone
Cost of 1 m2 canvas
= ₹70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost
of canvas = ₹ 13728/7 × 70 = ₹137280
Hence, required cost of the Canvas is
₹137280
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Hope this will help you....