under root 1 minus sin theta upon 1 + sin theta is equals to sec theta minus tan theta prove this
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Step-by-step explanation:
(1-sinx/1+sinx)½
(1-sinx/1+sinx * 1-sinx/1-sinx)½
((1-sinx)²/1-sin²x)½
((1-sinx)²/cos²x)½
1 - sinx / cosx
1/cosx - sinx/cosx
secx - tanx
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