Under root
1 + sin square theta into sec square theta upon 1 + cos square theta into cos square theta cos 2 theta
Answers
Answered by
0
Answer:
Answer
(1−cos
2
θ)sec
2
θ
=
sin
2
θ×sec
2
θ
=sinθ×secθ
=
cosθ
sinθ
=tanθ
Hence True.
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