Question

Under root 112 - under root80/ under root20- under root28 =????

Answer 1

Answer:

The answer is 2

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Answer 2

Answer

(112-√80)/(√20+-√28)=2

step by step explain

(√112-√80)/(√20-√28)

(√2*2*28-√ 2*2*20)/(√ 20- √28)

(2 √28-2 √20)/√ 20-28)

2(√ 28+-√ 20)/( √20- √20)

-2(√-20+- √28)/( √20-√ 28)

-2