Question

under root 3 into x minus 2 is equals to 2 under root 3 plus 4

Answer 1

$\sqrt{3} x - 2 = 2 \sqrt{3} + 4$

$\sqrt{3} x = 2 \sqrt{3} + 4 + 2$

$\sqrt{3} x = 2 \sqrt{3} + 6$

$\sqrt{3} x = \sqrt{3} (2 + 2 \sqrt{3} )$

$x = 2 + 2 \sqrt{3}$


Thanks