Math, asked by kushal2972, 1 year ago

under root 3 minus underroot 2 the whole square​

Answers

Answered by jagdeepsingh4076
0

(√3-√2)^2

Answer : 5-2√6

Explanation :

(a−b)^2 =a^2−2ab+b^2

  =  &gt; { \sqrt{3} }^{2}  +  { \sqrt{2} }^{2}  - 2 \times  \sqrt{3}  \times  \sqrt{2}  </h3><p></p><h3>\\  =  &gt; 3 + 2 - 2 \times  \sqrt{6}</h3><p> </p><h3>\\  =  &gt;  5 - 2 \sqrt{6}

(according to the BODMAS)

I hope you like this.....

Answered by rishabhsingh0156
0

let me solve

i will tell you

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