Question

under root 3 X square + 10 X + 7 under root 3 equal to zero solve ​

Answer 1

Answer:

√3x^2 + 10x +7√3 = 0

√3x^2 + 7x +3x +7√3=0

x(√3x+7) +√3(√3x +7) =0

(x+√3) + (√3x + 7) = 0

x= -√3 and x= -7/√3

hope this will help you..

Answer 2

$\bold\red \star \: \underline{Question:-}$

$\red{ Q. } \: \: \: \sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} = 0.$

$\bold\red \star \: \underline{Solution:-}$

$\sqrt{3 } {x}^{2} + 10x + 7 \sqrt{3} = 0. \\ \\ \sqrt{3} {x}^{2} + 7x + 3x + 7 \sqrt{3} = 0 .$

_______________Or________________

$\\ \\\sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} = 0. \\ \\ \sqrt{3} x(x + \sqrt{3} ) + 7(x + \sqrt{3} ) = 0. \\ \\ \sqrt{3} x + 7 = 0. \: \: \: \: \red{or} \: \: \: \: x + \sqrt{3} = 0. \\ \\ x = \frac{7}{ \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red {or} \: \: \: \: \: \: \: x = - \sqrt{3}.$

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$\\ \\ \purple {\ll{Rationalizing.}}$

$x = \frac{7}{ \sqrt{3} } . \\ \\ \: \: \: \: = \frac{7}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3}} . \\ \\ \: \: \: \: = \frac{7 \sqrt{3} }{3}.$

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$Our \: \: Answer... \\ \\ x = - \sqrt{3} \: \: \: \: \: \: \: \: \: \red{ or} \: \: \: \: \: \: x = \frac{7 \sqrt{3} }{3} .$