Question

under root 3 x square minus 2 under root 2 x minus 2 under root 3 is equal to zero

Answer 1

√3x^2-3√2x+√2x-2√3=0

√3x(x-√6+√2(x-√6)=0

(√3x+√2)(x-√6)=0

X=-√2/√3 or x=√6

This ans may help you

Answer 2

Answer:

$x=\sqrt{6}\: Or \: x=-\frac{\sqrt{2}}{\sqrt{3}}$

Step-by-step explanation:

$Given \: Quadratic \: equation:\\\sqrt{3}x^{2}-2\sqrt{2}x-2\sqrt{3}=0$

\* Splitting the middle term,we get

$\implies \sqrt{3}x^{2}-3\sqrt{2}x+\sqrt{2}x-2\sqrt{3}=0$

$\implies \sqrt{3}x^{2}-\sqrt{3}\sqrt{6}x+\sqrt{2}x-\sqrt{2}\times \sqrt{6}=0$

$\implies \sqrt{3}(x-\sqrt{6})+\sqrt{2}(x-\sqrt{6})=0$

$\implies (x-\sqrt{6})(\sqrt{3}x+\sqrt{2})=0$

$\implies (x-\sqrt{6})=0\: Or \: (\sqrt{3}x+\sqrt{2})=0$

$\implies x=\sqrt{6}\: Or \: \sqrt{3}x=-\sqrt{2}$

$\implies x=\sqrt{6}\: Or \: x=-\frac{\sqrt{2}}{\sqrt{3}}$

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