Question

under root 32 ÷ under root 2 please answer correct​

Answer 1

Answer:

The answer is 4

Step-by-step explanation:

   $\dfrac{\sqrt {32}}{\sqrt 2}=\sqrt{\dfrac{32}{2}}=\sqrt{16}=4$

Note: If $a,b$ are positive numbers, then

           $\sqrt a\times \sqrt b=\sqrt{ab}$ and  $\dfrac{\sqrt a}{\sqrt b}=\sqrt\dfrac{a}{b}$

Answer 2

Answer:

root 32 ÷  root 2 = 4

Step-by-step explanation:

$\frac{\sqrt{32} }{ \sqrt{2} } = \frac{\sqrt{16\times 2} }{ \sqrt{2} }\\= \frac{4\sqrt{ 2} }{ \sqrt{2} }\\= 4$