Math, asked by ranjanakarup, 8 months ago

under root 32 + under root 48 by under root 8 + under root 2​

Answers

Answered by anshi60
28

Answer:-

 \sqrt{32}  +  \frac{ \sqrt{48} }{ \sqrt{8} }  +  \sqrt{2}  \\  \\  =  \sqrt{2  \times 2 \times 2 \times 2 \times 2}   \:  +  \frac{ \sqrt{2 \times 2 \times 2 \times 2 \times 3} }{ \sqrt{2 \times 2 \times 2} }  +  \sqrt{2}  \\  \\  = 4 \sqrt{2}  +  \frac{4 \sqrt{3} }{2 \sqrt{3} }  +  \sqrt{2}  \\  \\  = 4 \sqrt{2}  +  \frac{2 \sqrt{3} }{ \sqrt{3} }  +  \sqrt{2}  \\  \\  = 5 \sqrt{2}  +  \frac{2 \sqrt{3}  \times  \sqrt{3} }{ \sqrt{3}  \times  \sqrt{3} }  \\  \\  = 5 \sqrt{2}  +  \frac{6}{3}  \\  \\  = 5 \sqrt{2}  + 2

Answered by sy45764
0

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