Math, asked by kumarpawan7154, 1 year ago

Under root 3x square -root 2x+root 3 =0.solve

Answers

Answered by Anonymous
2

( \sqrt{3x} ) {}^{2}  -  \sqrt{2x}  +  \sqrt{3} \\ 3x -  \sqrt{2x}  +  \sqrt{3}
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