Question

under root 5 Ek aparimey sankhya Hai Siddh kijiye​

Answer 1

Answer:

Step-by-step explanation:let root 5 is a rational number

root 5 = a/b [b≠0 HCF=1]

sq. Both sides

5=a²/b²

a²=5b²

5 divides a²

5 divides a. (1).....

a=5c (c is integer)

Sq. Both sides

a²=25c²

from eq. 1

5b²=25c²

b²=5c²

5 divides b²

5 divides b

Then, 5 is common in both

This contradict our assumption

So, root 5 is an irrational number