Question

under root 6 + under root 6 =?​

Answer 1

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See, you have to understand the under roots as x. Then √6 = x

$\sqrt{6} + \sqrt{6} = x + x$

$\sqrt{6} + \sqrt{6} = 2x$

Now substitute the value of x = √6

$\sqrt{6} + \sqrt{6} = 2 \sqrt{6}$