Math, asked by tushar195, 1 year ago

under root 6 + under root 6 + under root 6 infinity

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Answered by shivani12320

Hope it is helpful..

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Anonymous: we have to find value of x which is 3 n u r adding it to 6 it will be 3 raise to power 2 is 9=6+x

Anonymous: x=3

shivani12320: the answer is 3 .... would I wrote something wrong..

Anonymous: yeah u've written 9

shivani12320: in this, I just checked. i.e, Lhs=rhs

Anonymous: ook

Answered by Anonymous

Just check out YouTube but I've got a solution.
$x = \sqrt{6 \sqrt{6 \sqrt{6 \sqrt{6.......} } } }$
$x = \sqrt{6 + x}$
${x}^{2} = \sqrt{6 + x {}^{2} }$
${x}^{2} = 6 + x$
$value \: ofx \: will\: be \: 3$
$3 raise to power 2 = 6 + 3$
$value \: of \: x \: is \: 3$
THE ANSWER IS 3.
Hope it'll be helpful.it

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