Question

under root 72 + under root 18 + under root 112

Answer 1

$\sqrt{72} + \sqrt{18} + \sqrt{112} \\ \\ = \sqrt{2 \times 2 \times 3 \times 3 \times 2} + \sqrt{2 \times 3 \times 3} + \sqrt{ 2 \times 2 \times 2 \times 2 \times 7 } \\ \\ = 6 \sqrt{2} + 3 \sqrt{2} + 4 \sqrt{7} \\ \\ = 9 \sqrt{2} + 4 \sqrt{7}$
=9√2 +4√7